Postgresql replace value in array11/16/2023 ![]() I think that should work in 8.1 but I don't have access to 8.1 to check. The ARRAYREPLACE() is an inbuilt array function in Postgres that allows us to replace all the occurrences of an array element with a new element. If you're stuck in the 8.1 stone age and can't do anything about it, then perhaps something like this would work: create or replace function ff(int, text) returns integer as $$ UPDATE mytable SET factorslist arrayreplace (factorslist, 'Infinity', 99999999) WHERE TRUE recommend to first copy some rows into a test table and update those, SELECT INTO testtable FROM columns LIMIT 1000. You could also use regexp_split_to_table: create or replace function ff(int, text) returns integer as $$įrom regexp_split_to_table($2, ',') as dt(s) I have 2 text columns where I need to replace (on update) chars from array 1 ('q','x','y','z') to their index-equivalent value in array 2 ('a','b','c','d'). I've also corrected some typos ( RETRUNS, RETRUN, and pgsql) along the way. select construct: create or replace function ff(int, text) returns integer as $$įrom unnest(string_to_array($2, ',')) as dt(s) Then use it in whatever part of your query that makes sense.You don't need a loop for that, you could use unnest to convert the array from string_to_array into a set of rows and then use a simple insert. This will output: REGEXP_REPLACE(REGEXP_REPLACE('input test string, 'test', '', 'gi'), 'foo', '', 'gi') So that finally, when no more substrings are in the list to remove, the final aggregated query is returned. Then, recursively calls the function again with elements and append each REGEXP query to the passed parameter. The code splits the comma separated string to a list of substrings to remove, Creates a REGEXP_REPLACE function in sql with the first substring. ![]() Replace_psql_string("test,foo", "input test string") Return self.replace_psql_string(','.join(ss), query) This is a generic recursive function written in python (but can easily be replicated in whatever language you prefer) That takes in the original string and a list of substrings to be removed: def replace_psql_string(str_to_remove, query): ![]() Replace characters with multi-character strings The result of the update is following: Juhanao Updates table so all predefined letters are translated and the change is saved to the database. update xyz set name = translate(name, 'ä,ü,Ü', 'a,u,U') Translates all letters ä to a, ü to u and Ü to U. The result of the update is following: JuhaenaeoĮxample of translate function: select translate(name, 'ä,ü,Ü', 'a,u,U') from xyz Is there a way to use an input array of values as a way to replace different string occurrences in one go Say we have an input array of 'a', 'b', 'c', 'd', and a replacement array of '1', '2', '3', '4'. update xyz set name = replace(replace(replace(name, 'ä', 'ae'), 'ü', 'ue'), 'Ü', 'Ue') Ĭhanges letters and updates rows. Not very nice, but in the example all ä become ae, ü become ue, and Ü become 'Ue'. But the two approaches differ importantly: arrayreplace () changes all values that match the specified value to the same new value, insensitively to their. select replace(replace(replace(name, 'ä', 'ae'), 'ü', 'ue'), 'Ü', 'Ue') from xyz Each of the approaches described in this section, using the arrayreplace () function and setting an addressed array value explicitly and in place, can be used to change values in an array. select replace(name, 'ä', 'ae') from xyz Arrays of any built-in or user-defined base type, enum type, composite type, range type, or domain can be created. This function replaces letter ä in the name column with letter a. PostgreSQL allows columns of a table to be defined as variable-length multidimensional arrays. Some data to play with: drop table if exists xyz Įxample of replace function: select replace(name, 'ä', 'a') from xyz If you want to translate some letters to other letters you can user function translate(string text, from text, to text) that replaces any character in a string that matches a character in the from by the corresponding character in the to set. Finally do the update with: UPDATE mytable t SET mydata s.myarray FROM ( - query ) s WHERE t.id s.id. The replace function can be used to replace one character to several characters. Now you can use these indexes to place the new 'TV' element to the right place with jsonbset () Afterwards you need to remove the old 'Tv' element from the updated array. If you want just to replace one or few characters you can use function replace(string text, from text, to text) that replaces all occurrences in string substring.
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